To allocate 50 BMI values in an array you write down inway1

To allocate 50 BMI values in an array, you write down in//way-1 int size = 50; double[] BMI = new double[size]; could you write it this//way-2: int size = 50; double[] BMI; BMI = new double[size]; ANS: circle Yes Or No You have defined an array named: double bmi[] = new double[]; and fill it out full with contents, and you would like to access the value of second element and assign the value to a variable defined as: double b; write the code for the operation. ANS: Here is an array declaration containing income values for five years consecutively: int[] income = {1200, 1000, 1700, 1300, 2000}; int i; int howManyYears = income.length;//to display the 3^rd year income, in this statement System.out.print (3^rd year income^-\" + income[i]; What should be the value of index i? ANS What is the value of variable; howManyYears? ANS ANS: index i = ANS: What is wrong with the following code to initialize an array BMI for every element to zero? To compile this code, will compiler generate any syntax error? If compilation is passed, what would happen when the byte code is executed? Explain in detail ANS double[] bmi = new double[20]; for (int i = 1; i

Solution

26) Yes, both are same.

27) double b = bmi[1], the values are accessed starting with 0, so to access the second number we use 1.

28) (1) 2, to access the 1st element with 0 and increment, so to access the 3rd element we use 2.

(2)5, the variable will hold the length of the array which is 5.

29) (1) No, the function will compile perfectly.

(2) The loop runs from i=1 to 20. When i reaches 20, BMI[20] does not exist so it will throw an illegal memory access exception.