Stuck on this question Suppose you are investing 5000 one po

Stuck on this question. Suppose you are investing $5,000, one portion at 9% and the remainder at 4%. If x is the amount invested at 9%, write an algebraic expression describing total annual income from both investments.

a) .09x + .04(1-x)

b) 450 -.05x

c) . 09(5000-x) +.04x

d) 200 + .05x

Solution

investing $5,000, one portion at 9% and the remainder at 4%.

If x is the amount invested at 9% Income from this amount = x*9/100 = 0.09x

Remaining = 5000 -x invested at 4% , income from this investement = (5000-x)*4/100

                                 = 0.04(5000 -x)

= 200 - 0.04x

Total income = 0.09x + 200 -0.04x = 0.05x +200

Option d