FOR THIS QUESTION YOU MUST DO THE PROBLEM BY HAND DO NOT USE

(**FOR THIS QUESTION YOU MUST DO THE PROBLEM BY HAND. DO NOT USE THE ONLINE CALCULATOR) A normal mean content of lysine in cow\'s milk is known to be 275mg/100mL. Ten cows were placed on an experimental ration that is expected to increase lysine in the milk if in fact it has any effect at all on lysine. Data: 255, 268, 278, 262, 282, 284, 318, 258, 314, 295 What is the P-value of the test? (Carry your answer to 4 decimal places).

Solution

Set Up Hypothesis
Null, H0: U=275
Alternate, H1: U>275
Test Statistic
Population Mean(U)=275
Sample X(Mean)=281.4
Standard Deviation(S.D)=22.127
Number (n)=10
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =281.4-275/(22.127/Sqrt(9))
to =0.915
| to | =0.915
P-Value :Right Tail - Ha : ( P > 0.9147 ) = 0.19211