In a manufacturing process the useful life of a cutting tool
Solution
A)
Using technology, we get
slope = -0.111
intercept = 9.356666667
Thus, the regression line is
y^ = -0.111x + 9.356666667 [ANSWER]
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B)
Also, getting the correlation,
r = -0.950776834
Thus, the coefficient of determination is
r^2 = 0.903976587
Thus, about 90.398% of the variation in useful life can be eplained by the cutting speed. [ANSWER, 90.398%]
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c)
Thus, if x = 55
Then
y^ = 3.251666667
The standard error of the estimate is
sy = 0.549568595
We first get the z score for the critical value. As z = (x - y^) / sy, then as
x = critical value = 4
y^ = mean = 3.251666667
sy = standard deviation = 0.549568595
Thus,
z = 1.36167412
Thus, using a table/technology, the right tailed area of this is
P(z > 1.36167412 ) = 0.086650376 [ANSWER]
