Solve for x 2sin4x4sin2xSolution2sin4x4sin2x 2sin22x4sin2x s

Solve for x

2sin(4x)=-4sin(2x)

2sin(2*2x)=-4sin(2x)

sin2A=2sinAcosA

2*2sin(2x)cos(2x)=-4sin(2x)

4sin(2x)cos(2x)=-4sin(2x)

4sin(2x)cos(2x) +4sin(2x)=0

4sin(2x)(cos(2x)+1)=0

sin(2x)=0 ,cos(2x)=-1

sin(2x)=0

=>2x =n

=>x=n/2

cos(2x)=-1

=>2x =2n- ,2n+

=>x =n-(/2) ,n+(/2)

therefore x =n/2 ,n-(/2) ,n+(/2) , where n is integrer