Homework SourseA survey of 300 students selected randomly on a large univer
A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found.
A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found.
A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found.
Solution
As
p^ = 0.35
SE = 0.028
Then the approximate 95% confidence interval is obtained by adding and subtracting 2SE from the mean proportion. Hence,
lower bound = 0.35 - 2*0.028 = 0.294
upper bound = 0.35 + 2*0.028 = 0.406
Thus, the confidence interval is
(0.294, 0.406) [ANSWER]
