The pages are in numerical order STA3032 Exam 1 Continued Qu

The pages are in numerical order:

STA3032 Exam 1 (Continued) Questions through refer to the following problem: A box contains 20 resistors. Eight of them are rated at 50 and the other twelve are rated at 100 . Two resistors are selected at random. I. (1 point) What is the probability that the first resistor is rated at 100 ? 2. (2 points) what is the probability that the second resistor is rated at 100 , given that the first resistor is rated at 50 ? Page 2 of 13 Please go on to the next page.

Solution

Q4 .
P( Lot A is confirming) = 88/ (88+12) = 0.88

Q5.
P( Confirming but n\'t From C) = 1 - P( Confirming from C) = 1 - 260/(260+165+88) = 0.4931

Q6.
P( Lot C is confirming ) = 260 / (260+40) = 0.8667

Q7.
Let P(A) = (88+12) / (88+12+165+45+260+40) = 0.1639
    P(B) = (88+1665+260) / (88+12+165+45+260+40) = 0.8409
    P( A n B) = 88 / (88+12+165+45+260+40)= 0.1442
P(A) * P(B) = 0.1378

P(A) * P(B) ! = P(A n B) , not independent events

Note: ask the rest of the questions in another thread