Plant Number 1 2 3 4 5 6 Before program 44 57 47 66 50 36 Af

Plant Number

1

2

3

4

5

6

Before program

44

57

47

66

50

36

After Program

36

50

43

61

49

29

Plant Number

1

2

3

4

5

6

Before program

44

57

47

66

50

36

After Program

36

50

43

61

49

29

Solution

Let us find mean, std deviation before and after program.

mu1 = 50: s1 = 9.54: n1 = 6

mu2 = 44.67 s2 = 10.31 n2 =6

-------------------------------------------------------------

t statistic = 0.2631

p value = 0.3975

As p value is more than 0.05 , accept null hypothesis.

There is no effective change after the training program.

 Plant Number 1 2 3 4 5 6 Before program 44 57 47 66 50 36 After Program 36 50 43 61 49 29 Plant Number 1 2 3 4 5 6 Before program 44 57 47 66 50 36 After Progr
 Plant Number 1 2 3 4 5 6 Before program 44 57 47 66 50 36 After Program 36 50 43 61 49 29 Plant Number 1 2 3 4 5 6 Before program 44 57 47 66 50 36 After Progr

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