A string of length L 2 m mass 01 kg is vibrating based equa

A string of length L = 2 m mass 0.1 kg is vibrating based equation q(x,t)=(.03m)e^i omega t sin (3 pi X/L) where omega = 10S^-1 What is its total energy?

Solution

E = (1/4)M ²A²

E=0.25*(0.1)(10*10)(0.03*0.1)²

E=2.25*10^-5 kgm/s²