An infinitely long coaxial cable consists of an inner conduc
Solution
The coax has an outer diameter b, and an inner diameter a. The space between the conductors is filled with dielectric material of permittivity . Say a voltage V0 is placed across the conductors, such that the electric potential of the outer conductor is zero, and the electric potential of the inner conductor is V0.
The potential difference between the inner and outer conductor is therefore V0 – 0 = V0 volts.
Poisson’s equation reduces to Laplace’s equation: ( ) 2 V r 0 = This particular problem (i.e., coaxial line) is directly solvable because the structure is cylindrically symmetric. Rotating the coax around the z-axis (i.e., in the ˆa direction) does not change the geometry at all. As a result, we know that the electric potential field is a function of only ! I.E.,: V (r ) =V ( ) This make the problem much easier. Laplace’s equation becomes:
