Solve the following problem for reaction forces at the suppo
Solve the following problem for reaction forces at the supports \"A\" & \"B\"
Solution
Since the object is stationary, moment of force about A is zero.
Therefore,
8x3-5sin(450)-3x9+10x12-FBx15=0
=> FB=7.56
Likewise, the moment of force about B is also zero.
Therefore,
10x3-3x6-5sin(45o)x9+8x12-FAx15=0
=> FA=5.08
