Solve the following problem for reaction forces at the suppo

Solve the following problem for reaction forces at the supports \"A\" & \"B\"

Solution

Since the object is stationary, moment of force about A is zero.

Therefore,

8x3-5sin(450)-3x9+10x12-FBx15=0

=> FB=7.56

Likewise, the moment of force about B is also zero.

Therefore,

10x3-3x6-5sin(45o)x9+8x12-FAx15=0

=> FA=5.08

 Solve the following problem for reaction forces at the supports \

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