question 1 Solutionrefracted angle r 29 deg Applying Snell

question 1

Solution

refracted angle , @r = 29 deg

Applying Snell\'s law to find incident angle,

ni sin@i = nr sin@r

1 * sin@i = 1.33 sin29

@i = 40.15 deg

In triangle above water made with real ray.

tan40.14 = 2 / h

h = 2.37 m .............Ans (a)

b) for triangle inside water, made with real ray.

tan29 = d / 2

d = 2 tan29 = 1.11 m   (Horizontal distance of diver)

now for triangle above water with virtual ray.

tan40.15 = d / h\'

h\' = 1.11 / tan40.15 = 1.31 m