Homework SourseGiven Ho p0 Ha p not 0 r 35 n24 Test the null hypothesis at
Given Ho: p=0; Ha: p not = 0; r +.35; n=24. Test the null hypothesis at alpha =.10, .05, .01
Solution
As
t = r*sqrt((n-2)/(1-r^2))
Then
t = 0.35*sqrt((24-2)/(1-0.35^2)) = 1.752491104
Thus, as df = n - 2 = 22, and this is two tailed, then the P value is, using table/technology,
P = 0.09361689
Thus,
As P < 0.10, Reject Ho at alpha = 0.10.
As P > 0.05, fail to Reject Ho at alpha = 0.05.
As P > 0.01, fail to Reject Ho at alpha = 0.01. [ANSWER]
