Homework SourseYou dilute a natural sample 106 plate it and determine that
You dilute a natural sample 10-6, plate it, and determine that the concentration of the diluted sample is 52 cells/ml. what was the initial concentration?
Solution
So initial concentration would be 52x106=52000000/ml
| Dilution | Colony/ml | |
| Stock | 52000000 | |
| 10-1 | 5200000 | |
| 10-2 | 520000 | |
| 10-3 | 52000 | |
| 10-4 | 5200 | |
| 10-5 | 520 | |
| 10-6 | 52 |
