The batting average of a baseball player is 0300 He comes to
The batting average of a baseball player is 0.300. He comes to bat four time. Find the probability that he will get: (a) exactly two hits; (b) at least one hit.
Solution
P(success) = 0.300
P(failure) = 0.700
a) exactly two hits
any two times he hit + any two times he miss the shot
= 4C2 * (0.7)^2 * (03)^2 = 0.2646
b) atleast one hit
= 1 - P(no hit)
= 1 - 4C0 * (0.7)^4 * (0.3)^4
= 1 - (0.7)^4 = 0.7599
