Refer to the circuit shown in the figure aWhat is the power

Refer to the circuit shown in the figure. (a)What is the power factor? (b)What is the average power dissipated? (c)What is the value of the capacitance that will give a unity power factor when connectcd to the load?

Solution

a) q=inverse tan(14/13)=47.121 degrees

power factor=cosq=cos(47.121)=0.68

b) average power=(v^2/z)=(120^2/(13+j14))=753.73<-47.12 watts