Consider the following differential equation 13330y 1170y

Consider the following differential equation 13.330y + 1.170y + 15.020y = sin(3.12t) + 1.48/t^2 + 0.43 with initial conditions, y(0) = 3.770(m) y(0) = 46.460 (m/s) Apply two steps of the fourth order Runge-Kutta method with Delta t = 0.200 to determine the velocity y(0.400).

Solution

ans)

Find the distance between the start and end points. When measuring velocity, the only positions that matter are where the object started, and where the object ended up. This, along with which direction the object traveled, tells you the displacement, or change in position. The path the object took between these two points does not matter. A car traveling due east starts at position x = 5 meters. After 8 seconds, the car is at position x = 41 meters. What was the car\'s displacement?

The car was displaced by (41m - 5m) = 36 meters east. A diver leaps 1 meter straight up off a diving board, then falls downward for 5 meters before hitting the water. What is the diver\'s displacement?

 Consider the following differential equation 13.330y + 1.170y + 15.020y = sin(3.12t) + 1.48/t^2 + 0.43 with initial conditions, y(0) = 3.770(m) y(0) = 46.460 (

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