c15p2 A harmonic wave moving in the positive x direction has

(c15p2) A harmonic wave moving in the positive x direction has an amplitude of 3.5 cm, a speed of 40.0 cm/s, and a wavelength of 22.0 cm. Assume that the displacement is zero at x = 0 and t = 0. Calculate the displacement (in cm) due to the wave at x = 0.0 cm, t = 2.0 s. velocity = wavelength * frequency Incorrect. Tries 2/7 Previous Tries Calculate the displacement due to the wave at x = 10.0 cm, t = 20.0 s.

Solution

the equation of harmonic wave is given as

y = A * sin(2pi/(wavelength)(vx - t))

y = 3.5 * sin(2pi/(22) * (40 * x - t))

at x = 0 cm , t = 2 s

y = 3.5 * sin(2pi/(22) * (40 * 0 - 2))

y = -1.89 cm

the displacement of the wave due to wave is -1.89 cm

-------------------

at x = 10 cm , t = 20 s

y = 3.5 * sin(2pi/(22) * (40 * 10 - 20))

y = 0 cm

the displacement of string is 0 cm