Frequency f Compare the mean of the raw data with the mean f

Frequency, f

Compare the mean of the raw data with the mean from the grouped frequency distribution. Are they different? Why might they be different?

261 275 236 244 278 296 284 298 289 289 250 256
338 360 341 333 261 268 287 296 313 311 309 309
299 303 277 283 304 305 286 290 286 287 297 299
332 330 309 326 309 326 285 291 295 298 306 315
310 318 318 320 333 321 323 324 327 302 319
Class

Frequency, f

Class Boundaries Class Midpoint, X fX
236-260 4 235.5-260.5 248 992
261-285 9 260.5-285.5 273 2457
286-310 26 285.5-310.5 298 7748
311-335 17 310.5-335.5 323 5491
336-360 3 335.5-360.5 348 1044

Solution

mean= (992+2457+7748+5491+1044)/(4+9+26+17+3) = 300.5424

Yes, they are different.

They might be different because the mean of the raw data is calculated directly from raw data, but the mean from the grouped frequency distribution is calculated by the grouped data.

Frequency, f Compare the mean of the raw data with the mean from the grouped frequency distribution. Are they different? Why might they be different? 261 275 23

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