Homework SourseThe frequency distribution below shows the distribution for
The frequency distribution below shows the distribution for checkout time (in minutes) in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon.
2. Complete the frequency table with frequency and relative frequency. Express the relative
frequency to two decimal places.
What percentage of the checkout times was at least 3 minutes?
In what class interval must the median lie? Explain your answer.
Does this distribution have positive skew or negative skew? Why?
(5 pts) (3 pts)
(5 pts) (2 pts)
| Checkout Times(In minutes) | Frequency | Relative Frequency |
| 1.0-1.9 | 3 | |
| 2.0-2.9 | 12 | |
| 3.0-3.9 | 0.20 | |
| 4.0-4.9 | 3 | |
| 5.0-5.9 | ||
| Total | 25 |
Solution
Relative frequency for 1-1.9 = 3/25 = 0.12
Frequency for 3 - 3.9= 25*0.2 = 5
For 5 - 5.9 is the total 25 - frequ of other rows
Similarly prob = 1- total of others
As cum frequency is 0.5 in 2-2.9, median lies here
This implies that this is right skewed
| Checkout Times(In minutes) | Frequency | Relative Frequency |
| 1.0-1.9 | 3 | 0.12 |
| 2.0-2.9 | 12 | 0.48 |
| 3.0-3.9 | 5 | 0.2 |
| 4.0-4.9 | 3 | 0.12 |
| 5.0-5.9 | 2 | 0.08 |
| Total | 25 | 1 |
