What is the live load if this floor is to be used in a typic

What is the live load if this floor is to be used in a typical residential dwelling?

(I\'m a little confused on this question? Is there a formula for live loads? or do i just put what the chart says below? Ive included the dead load with my calculations in case you need it)

Total weight is 6.4lb

Volume of a 1-ft-long joist = 0.14ft^3

Using the density of Douglas fir, which is 34lb

Weight of a 1-ft-long joist = (0.14) (34) = 4.8lb

A 1-ft-long floor joist carries 1.33ft^2 of floor

The weight of floor joist that contributes to 1ft^2 of the floor is 4.8 / 1.33 = 3.6lb

The total dead load of 1ft^2 of floor is 6.4lb + 3.6lb = 10lb

Residential dwellings Dwellings and hotel guest rooms 40 Habitable attics 30 Corridors, public spaces, and balconies 100

Solution

The permanent dead load calculated is okk...to calculate the imposed dead and imposed live load we should follow the given table or assume some appropriate values accordingbto the given conditions....since we have the floor is given ,we should simple multiply the imposed uniformly dead load and uniformly live load with joist floor area and sum up the all to calculate the total loads on the joist...