A parallelplate capacitor with adjustable plate separation d
Solution
(1)
capacitance: C = e0A/d,
charge Q = CV = [e0A/d]*V ,
and
energy = U = (1/2)CV^2 = (1/2) [e0A/d]*V^2
From above relation, energy U is inversely proportional to d.
So, energy U increases when d decreasing.
statement 1: true
2.)
charge Q is directly proportional to area A.
the charge increases when the area increases.
statement 2: false
3)
Capacitance C is directly proportional to area A.
the capacitance increases when the area increases.
statement 3: true
4)
charge Q isinversely proportional to distance d.
charge Q decreases when distance increases.
statement 4: true
5)
energy U is directly proportional to area A.
the energy increases when the area increases.
statement 5: false
6)
capacitance C isinversely proportional to distance d.
Capacitance C increases when distance dicreases.
statement 6: true


