k A large ballistic rocket vehicle has the following charact
Solution
a) The thrust equation for a rocket is given by
Thrust (N) = mVe + (pe po) Ae
m\' - mass flow rate of propellent, Ve - exit velocity (sea level), Pe- exit pressure at nozzle, Po- atmospheric pressure, Ae - exit area of the nozzle
replacing with the values,
Thrust (N) = 14.6 x 12 x 7100 x 0.3048 + ( 5 x 6894.76 - 14.7 x 6894.76 ) x 0.00064516 x 400
Thrust (N) = 379146.816 + (-16719.793) = 362427.023 N or 36.24 kN
b) effective velocity is the ratio of thrust over the mass rate,
F / m\' = veff where veff - effective exhaust velocity, F - thrust , m\' - mass flow rate of propellent
replacing with values,
(36.24 x 103 ) / (14.6 x 12) = 207.03 m/s
c) Initial thrust (F) = 36.24 kN or 36.24 x 103 (sea level) and Weight (take off) = 12 tons = 12 x 103 N
F / W = (36.24 x 103) / (12 x 103) = 3.02 (unitless)
d) Initial acceration (ai) = (v- u) / t, where v - final velocity (nozzle exit velocity) u - intial velocity, t - time (burning time)
ai = ( (7100 x 0.3048) - 0 ) / 50 = 43.28 m / s2
d) inverse mass flow ratio = mo / mf where mo - take off mass, mf = fuel mass (mass flow of propellent x burning time)
(12 x 103) / (7100 x 0.3048 x 50) = 0.1109 (dimensionless)
