Discrete Math There are 345 students at a college who have t

Discrete Math:

There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, and 188 who have taken courses in both calculus and discrete mathematics. How many students have taken a course in either calculus or discrete mathematics?

Solution

n(Calculus ) = 345

n(discrete Math ) = 212

n(Calculus intersection discrete mah ) = 188

n(Calculus union discrete math) = 345 + 212 - 188 = 369