A converging lens which has a focal length equal to 92 cm is

A converging lens, which has a focal length equal to 9.2 cm, is separated by 31.8 cm from a second lens. The second lens is a diverging lens that has a focal length equal to -13.4 cm. An object is 18.4 cm to the left of the first lens.

(a) Find the position of the final image using both a ray diagram and the thin-lens equation.
cm to the right of the object

(c) What is the overall lateral magnification?

----------------------------------------------------------------------------------------------------------------------------------

An object is 19.5 cm to the left of a lens that has a focal length of +8.50 cm. A second lens, which has a focal length of -28.0 cm, is 4.80 cm to the right of the first lens.

(a) Find the distance between the object and the final image formed by the second lens.
cm

(b) What is the overall magnification?

Solution

2.

From thin lens equation

1/f =1/S₁ + 1/S₁\'

For First lens ,Location of the image formed by the first lens

1/8.5 =1/19.5 + 1/S₁\'

S₁\' =15.07 cm

Since second lens is 4.8 cm to the right of first lens

S₂=4.8-15.07 =-10.27 cm

Now

1/f₂ =1/S₂ + 1/S₂\'

-1/28 = -1/10.27 +1/S₂\'

S₂\' =16.22 cm

b)

Magnification

M=m₁m₂ =(-S₁\'/S₁)(-S₂\'/S₂) =(15.07/19.5)(16.22/-10.27)

M=1.22