Find x and y and all marked sides or angles of the given par

Find x and y and all marked sides or angles of the given parallelograms.

a. x and 40 are alternate interrior angles
x= 40

In triangle ACD, cad + 110 + x = 180

cad +110+40 = 180
cad = 30

bca = cad = 30, alterate interior angles

In triangle bca, bca +40+30 = 180
bca = 110

y = 110

b) Now lengths of the 2 halves of the diagonals are equal.

So, 2x+1 = x+4
x = 3

y+1 = 2y-3
y = 4