Find h2 h0 and h3 for the following function Simplify your a

Find h(-2), h(0) and h(3) for the following function: Simplify your answer

h(x) = 6x^2+4

h(-2) =

h(0) =

h(3)=

To get answer for these kind of problems, we just replace the x with the number given.

Here, The given function is:

h(x) = 6x^2+4

Therefore,

h(-2) = 6(-2)^2+4 = 6(4) + 4 As -2^2 = -2 X -2 = +4

=> h(-2) = 24 + 4

=> h(-2) = 28

h(0) = 6(0)^2+4 = 6 X 0 + 4 As 0^2 = 0X0 = 0

=> h(0) = 0 + 4

=> h(0) = 4

h(3) = 6(3)^2+4 = 6 X 9 + 4 As 3^2 = 3 X 3 = 9

=> h(3) = 54 + 4

=> h(3) = 58