As many as you could help with would be appreciated Student

As many as you could help with would be appreciated! :)

Student Name: Class: 12/14/05 Change the measure to degrees, minutes, and seconds. 1. 155.29\' [A] 155o 16 36 [B] 155° 17\'24\" [C] 155° 17\'29 [D] 155° 29\' 43 2. 93.60 [A] 93° 35\' 60\" [B] 93° 60 3 [C] 93° 36\' 0 [D] 93° 32\' 38 Write the measure as a decimal to the nearest thousandth 3. 355° 57\' 5\" [A] 355.571° [B] 355.951 [C] 355.099 [D] 356.033° 4.-302° 56\' 10 [A]-302.936 [B]-302.561° C1-302.182° [D]-303.1 Advanced Mathematical Concepts Chapter 5: The Trigonometric Functions Form 1 Page 3

Solution

1. 155.29 deg

1 deg = 60 minutes

0.29 deg = 17.4 minutes

1 minute = 60 sec

so, 0.4 minute = 24sec

So, 155.29 deg = 155deg 17minutes 24 seconds

8) From triangle AC = sqrt( AB^2 - BC^2) = sqrt( 15^2 -12^2) = sqrt81 =9

cosA = 12/15 = 3/5

sinA = 9/15 = 3/5

tanA =9/12 = 3/4

9) csc(theta) = sqrt(65)/4

sin(theta) = 4/sqrt(65)

Base = sqrt( 65 - 16) = 7

So, cos(theta) = 7/sqrt(65)

sec(theta) = sqrt(65)/7

Option D