Solution7 Solution a p4 1 010200503 02 015 Answer b Pr

#7) Solution :

a) p(4) = 1- ( 0.1+0.2+0.05+0.3+ 0.2) = 0.15 Answer

b) Probability that the random variable X is greater than 2 = (0.3+0.15+0.2) = 0.65 Answer

c) Probability that the random variable X is 2 or less = ( 0.1+0.2+0.05) = 0.35 Answer

d) E(X) = ? [ x_i * P(x_i) ]
E(X) = 0*0.1 + 1*0.2 + 2*0.05 + 3*0.3 + 4*0.15 + 5*0.2 = 2.8 Answer