The angular velocity of a flywheel decreases uniformly from

The angular velocity of a flywheel decreases uniformly from 100 rev/min to 40 rev/min in 5 s. Find the angular acceleration and the number of revolutions made by the flywheel in 5 s interval. How many more seconds are required for the wheel to come to rest?

Solution

100 rev/min = 10.472rad/s =u
40 rev/min = 4.1888rad/s =v
a) v = u+at
4.1888 = 10.472+ 5a
a = -1.2566 rad/s^2
answer
b) s = ut + 0.5 at^2
s = 10.472 * 5 - 0.5 * 1.2566 * 25
s = 36.6525 rad
= 5.833 rev
answer

c) v = u+at
0 = 4.1888 - 1.2566 t
t = 3.333 s
answer