Please help me with part A and Part B If one person is rando

Please help me with part A and Part B.

If one person is randomly selected what is the probability that the person is a Nonsmoker given that the person is a woman? A) 0.826 B) 0.168 C) 0.440 D) 0.620 If one person is randomly selected what is the probability that the person is a Man given that the person is a Heavy Smoker? A) 0.500 B) 0.674 C) 0.444 D) 0.333

Solution

Q1.
P( Nonsmoker given that Person is women) = P(Nonsmoker and Women) / P(Women) = (418/948) / (506/948) = 418/506 = 0.826

Q2.
p( Man given that He is a Heavy Smoker) = P(Man and Heavy Smoker) / P( Heavy Smoker) = (36/948) / (81/948) = 36/81 = 0.444