1 The following probability distribution represents the numb
1. The following probability distribution represents the number of people living in a Household (X), and the probability of occurrence (P(X)). Compute the Expected Value (mean), the Variance and the Standard Deviation for this random variable.
X 1 2 3 4 5 6 7
P(X) .22 .35 .18 .13 .07 .03 .02
2. Use the binomial formula to compute the probability of a student getting 3 correct answers on a 7 question Quiz, if the probability of answering any one question correctly is 0.83.
3. Submit your answers to the following binomial questions. You may use the appendix tables 5 to answer parts a and b. According to a government study,15% of all children live in a household that has an income below the poverty level. If a random sample of 15 children is selected:
a) what is the probability that 4 or more live in poverty?
b) what is the probability that 3 live in poverty?
c) what is the expected number (mean) that live in poverty?
(please answer the whole question)
Solution
1) E(X)=sum(x*P(x))
V(X)=E(X^2)-(mean)^2
E(X^2)=sum(x^2*P(x))
sd(x)=sqrt(V(x))
E(X)=2.65
E(X^2)=9.13
V(X)=2.1075
sd(X)=sqrt(2.1075)=1.4517
2. n=7
x=3
p=0.83
P(x)=0.01671
Use BINOMDIST function in excel to find the above probability.
3. p=0.15
n=15
a) P(x>=4)=1-P(X<4)
P(X>=4)=1-0.987897=0.012103
b) x=3
P(x=3)=0.016662
c) E(X)=n*p=15*0.15=2.25
| x | P(x) | x*P(x) | x*x | x*x*P(x) |
| 1 | 0.22 | 0.22 | 1 | 0.22 |
| 2 | 0.35 | 0.7 | 4 | 1.4 |
| 3 | 0.18 | 0.54 | 9 | 1.62 |
| 4 | 0.13 | 0.52 | 16 | 2.08 |
| 5 | 0.07 | 0.35 | 25 | 1.75 |
| 6 | 0.03 | 0.18 | 36 | 1.08 |
| 7 | 0.02 | 0.14 | 49 | 0.98 |
| 2.65 | 9.13 |

