The augmented matrix of a linear system has been reduced by

The augmented matrix of a linear system has been reduced by row operations to the form shown. Continue the appropriate row operations and describe the solution set of the original system. [0 0 0 1 0 1 0 6 0 -1 1 3 -1 3 1 -5]

Solution

The last ie the 4th column represents the vector, b in the system Ax=b

So we have 4 rows ie 4 equations and 4 columns. One corresponds to b so 3 variables

Now look at the first row

First three entries are zero and then a non zero entry

So there is no solution. Because the variables be denoted by:x,y,z

So,

0*x+0*y+0*z=-1

ie 0=-1

which is not possible

Hence no solution.