Suppose that 500 parts arc tested in manufacturing and 10 ar
Solution
a)
Formulating the null and alternatuve hypotheses,          
           
 Ho:   p   >=   0.03
 Ha:   p   <   0.03
 As we see, the hypothesized po =   0.03      
 Getting the point estimate of p, p^,          
           
 p^ = x / n =    0.02      
           
 Getting the standard error of p^, sp,          
           
 sp = sqrt[po (1 - po)/n] =    0.007628892      
           
 Getting the z statistic,          
           
 z = (p^ - po)/sp =    -1.310806263      
           
 As this is a    1   tailed test, then, getting the p value,  
           
 p =    0.094961613   [ANSWER, P VALUE]
significance level = 0.05
As P > 0.05, we FAIL TO REJECT THE NULL HYPOTHESIS.
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B)
We can construct un upper tailed 95% confidence interval in part A. If the upper bound is less than 0.03, then we reject Ho. If the upper bound is greater than 0.03, we fail to reject Ho.

