Suppose that 500 parts arc tested in manufacturing and 10 ar
Solution
a)
Formulating the null and alternatuve hypotheses,
Ho: p >= 0.03
Ha: p < 0.03
As we see, the hypothesized po = 0.03
Getting the point estimate of p, p^,
p^ = x / n = 0.02
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.007628892
Getting the z statistic,
z = (p^ - po)/sp = -1.310806263
As this is a 1 tailed test, then, getting the p value,
p = 0.094961613 [ANSWER, P VALUE]
significance level = 0.05
As P > 0.05, we FAIL TO REJECT THE NULL HYPOTHESIS.
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B)
We can construct un upper tailed 95% confidence interval in part A. If the upper bound is less than 0.03, then we reject Ho. If the upper bound is greater than 0.03, we fail to reject Ho.
