In randomized doubleblind clinical trials of a new vaccine r

In randomized, double-blind clinical trials of a new vaccine, rats were randomly divided into two groups. Subjects in group 1 received the new vaccine while subjects in group 2 received a control vaccine. After the first dose, 119 of 748 subjects in the experimental group (group 1) experienced fever as a side effect. After the first dose, 69 of 640 of the subjects in the control group (group 2 experienced fever as a side effect. Construct a 90% confidence interval for the difference between the two population proportions, p p2. Use x1 S1 n 748, x 69, and n 640 119, The 90% confidence interval for p p, is b (Use ascending order. Round to three decimal places as needed.)

Solution

Confidence Interval for Diffrence of Proportion
CI = (p1 - p2) ± Z a/2 Sqrt(p1(1-p1)/n1 + p2(1-p2)/n2 )
Proportion 1
Probability Succuses( X1 )=119
No.Of Observed (n1)=748
P1= X1/n1=0.159
Proportion 2
Probability Succuses(X2)=69
No.Of Observed (n2)=640
P2= X2/n2=0.108
C.I = (0.159-0.108) ±Z a/2 * Sqrt( (0.159*0.841/748) + (0.108*0.892/640) )
=(0.159-0.108) ± 1.64* Sqrt(0)
=0.051-0.03,0.051+0.03
=[0.022,0.081]