A multiple choice exam contains 10 questions There are four
Solution
A)Number of ways a student can answer the question on the exam if every question is answered=410
B)Number of ways a student can answer the question on the exam he can leave blank=510
Because we can treat leaving the question as one more option so we have total 5 options to answer.
C) To get 70 % student needs to give 7 correct answers
so now number of way to choose to the 7 correct answers out of the 10 question=10C7
now think about the remaining 3 question
number of ways to answer the remaing 3 question=43
So total number of ways to get exact 70 % = 10C7 *43
TO get 80 % ,student need to give 8 correct answers
so now number of way to choose to the 8 correct answers out of the 10 question=10C8
now think about the remaining 2 question
number of ways to answer the remaing 2 question=42
So total number of ways to get exact 80 % = 10C8 *42
TO get 90 % ,student need to give 9 correct answers
so now number of way to choose to the 9 correct answers out of the 10 question=10C9
now think about the remaining 1 question
number of ways to answer the remaing 1 question=41
So total number of ways to get exact 90 % = 10C9 *41
TO get 100 % ,student need to give all answers correct
so now number of way to choose to the 10 correct answers out of the 10 question=10C10
so now total number of ways to get at least 70 %= 10C7 *43 +10C8 *42 +10C9 *41 +10C10
so the number possibillities to get 70 % or higher on exam =10C7 *43 +10C8 *42 +10C9 *41 +10C10
