in the pV diagram below the gas does 12J of work along isoth
in the p-V diagram below, the gas does 12J of work along isotherm ab to 3J of work along adiabat bc. what is the internal energy if the gas traverses the straight path from a to c? justify your answer
Solution
Along ab temperature T is constant.
For ideal gas, internal energy E= constant and delta E= 0.
E(internal)= nCvT
along bc: Q=0
From first law of thermodynamics:
E(internal)=Q+W
Here W is the work done on the system.
=0+W=-4J
Here negative sign indicates the work is done by the system. Change in internal energy is independent of the path taken.
E(internal)= -4J
