A threephase short transmission line having a perphase imped
A three-phase short transmission line having a per-phase impedance of (2 + j4) Ohm has equal line-to-linc receiving-end and sending-end voltages of 115 kV while supplying a load at 0.8 power factor leading. Calculate the power supplied by the line.
Solution
P=VsVcos(a-b)/z
a=power factor angle
b=impendnce angle
a=inverse cos(0.8)=36.36
b=angle(2+4i)=63.43
z=mag(2+4i)=4.472
p=(115*115*cos(36-63))/4.47*3
p=870mw
