In a population of 1000 snapdragon plants 200 are red flower

In a population of 1000 snapdragon plants, 200 are red flowered (A^1 A^1), 100 are pink flowered (A^1 A^2) and 700 are white flowered (A^2 A^2). (Note that flower color shows incomplete dominance, so we do not use uppercase and lowercase letters for alleles. Again, you can arbitrarily designate p as the frequency of A^1 and q as the frequency of A^2) Calculate the fixation index (F) for this population. (Begin this problem like a standard HWE problem Calculate observed genotype frequencies, and from that allele frequencies. Plug into HWE to get expected heterozygosity for the population F equation.

Solution

Answer:

According to Hardy weinberg principle = p² + 2pq+ q²

Frequency of heterozygous individuals (2pq) = 100/1000 =0.1

Frequency of the dominant allele = p2 = 200/1000 = 1/5 = 0.2

                                                   p2 = 0.2,   p= 0.44

Frequency of the recessive allele = q2 = 700/1000 = 0.7

                                                    q2 = 0.83