You are given the following information from a life tablI90

You are given the following information from a life tablI90 = 1000 and I93 = 825Deaths are uniformly distributed over each year of age.Calculate the probability that (90) dies between ages 93 and 95.5. (Ans 0.345)

Solution

Using the formulae dx=qxlx , dx=lx-lx+1 and lx+1=pxlx we complete the life table as follows,

We assume that the number of death between ages x and x+1 is uniformly distributed.

Given l90=1000 and l93=825.

From the table l95=600 and l96=360.

Required P[a person aged 90 dies betwen ages 93 and 95.5]

              = (No. of deaths between 93 and 95.5)/(No. of persons aged 90)

              = { (l93-l95)+d95/2 }/1000     (Since deaths are uniform between ages)

              = {825-600+120}/1000

              = 0.345      (Ans.)

x lx dx px qx
95 600 240 0.6 0.4
96 360 288 0.2 0.8
97 72 72 0.0 1.0
 You are given the following information from a life tablI90 = 1000 and I93 = 825Deaths are uniformly distributed over each year of age.Calculate the probabilit

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