You are given the following information from a life tablI90
You are given the following information from a life tablI90 = 1000 and I93 = 825Deaths are uniformly distributed over each year of age.Calculate the probability that (90) dies between ages 93 and 95.5. (Ans 0.345)
Solution
Using the formulae dx=qxlx , dx=lx-lx+1 and lx+1=pxlx we complete the life table as follows,
We assume that the number of death between ages x and x+1 is uniformly distributed.
Given l90=1000 and l93=825.
From the table l95=600 and l96=360.
Required P[a person aged 90 dies betwen ages 93 and 95.5]
= (No. of deaths between 93 and 95.5)/(No. of persons aged 90)
= { (l93-l95)+d95/2 }/1000 (Since deaths are uniform between ages)
= {825-600+120}/1000
= 0.345 (Ans.)
| x | lx | dx | px | qx |
| 95 | 600 | 240 | 0.6 | 0.4 |
| 96 | 360 | 288 | 0.2 | 0.8 |
| 97 | 72 | 72 | 0.0 | 1.0 |
