One vertex and one focus of the ellipse whose equation is x

One vertex and one focus of the ellipse whose equation is (x - 1)^2/9 + (y - 4)^2/4 = 1 would be F = (1 + Squareroot 5, 4) & V = (4, 4) F = (1, 4) & V = (-2, 4) F = (4, 4) & V = (4, 0) F = (4, 4) & V = (4, 1 - Squareroot 5) What is the equation of a parabola whose vertex is the origin and whose directrix is the line x = 8? x^2 = 32y y^2 =32x x^2 = -32y y^2 = -32x

Solution

19) (x - 1)^2/9 + (y - 4)^2/4 = 1

Vertex =

Focus = (1 + sqrt(5), 4) =============> (option a))

20)

20) Vertex = (0, 0)

Directrix ====> x = 8

then x^2 = 32y (option A)