find tensileSolutionTo find tensile stress it is good to kno

find tensile

Solution

To find tensile stress, it is good to know basic definition of stress. Stress is nothing but force acting per unit area. As the force (P) applied here leads to tensile, we have to calculate tensile stress.

Tensile Stress = Force (or) Axial Load/Cross-section area = P/A

At Cross-section A-A:

P=45KN ; A= 45 * 30 mm² = 1350 mm² (The dimension is not clear in the picture; so i assumed it as 30) [The cross-section is rectangle; Area of rectangle is Length x Breadth]

Tensile Stress = 45x 1000 / 45 x 30 = 33.33 MPa (or) 33.33 N/mm²

At Cross-section B-B:

P=45KN ; A= pi/4 x (outer diameter² - inner diameter²) mm² = 3.14/4 x (75² - 40²) = 3159.625 mm²

[The cross-section is concentric circle; Area of circle is pi/4 x diameter²]

Tensile Stress = 45x 1000 / 3159.625 = 14.242 MPa (or) 14.242 N/mm²

Some inferences from results:

- Stress is more at section A-A than section B-B. This is because, area of cross-section is less in A-A compared to B-B. It means, the load gets distributed over the area.