Homework Soursea At what tilt should the PV modules be fixed to utilize gre
a. At what tilt should the PV modules be fixed to utilize greatest amount of the annual solar radiation?
b. Based on the average solar resource determined in Part (a), what is the minimum number PV modules that are required to generate 100% of the electricity used by the household?
Solution
Averaging the Radiation based on tilt angles of the location considered
So from above table average monthly Radiation is higher for Lat tilt angle . 4.775 kWh/m2/day
b. Minimum no.of Modules required to support load of 100 % is
Annually Energy Consumed by the Load is 4700 kWh
Average Energy Required Per day is 12.8767 kWh
Energy generated per kW solar PV system is = 5*2*0.18*0.7 *4.775 = 6.016 kWh
where 5*2 m2 area of PV system. We require 5 modules per kW system each 2 m2 area generates 140 W.
Over all efficiency of module is 0.18*(140/200) = 0.126
PV system required to meet this load is = 12.8767/(6.016) = = 2.1 kW
No.of Modules required = 2100/200 = 11 modules
| Tilt (0) | Sum of Daily radiation per year | Average Daily Radiation |
| 0 | 2+2.8+3.8+4.9+5.8+6.5+6.5+5.7+4.4+3.2+2.1+1.7 = 49.4 | 4.11667 |
| Lat - 15 | 3.2+3.9+4.6+5.3+5.9+6.4+6.5+6+5.2+4.4+3.1+2.6 = 57.1 | 4.7583 |
| Lat | 3.6+4.3+4.7+5.2+5.5+5.8+6+5.8+5.3+4.7+3.4+3 = 57.3 | 4.775 |
| Lat+15 | 3.9+4.4+4.7+4.8+4.9+5.1+5.2+5.3+5.1+4.7+3.6+3.2 = 54.9 | 4.575 |
| 90 | 3.7+4+3.+3.2+2.8+2.7+2.8+3.2+3.+3.9+3.2+3.1 = 39.8 | 3.316 |
