1 point Find the particular solution ofthe differential equa

(1 point Find the particular solution ofthe differential equation satisfying the initial condition y(0) 4 Answer: y(x) dy t y cos(x) F 2 cos(x)

This is Linear Differential Equation. Here, P = cos x.

Integral of P dx = Integral of cos x dx =sin x.

Solution is:

y exp (sin x) = 2 Integral of exp (sin x) d(sin x)

= 2 exp (sin x) + C, where C is the constant of integration.

To get value of C:

Given: At x=0, y=4.

Substituting in the above equation, we get:

4 = 2 + C.

So, C=2.

Substituting the value of C in the solution, we get,

y exp (sinx ) = 2 exp (sin x) + 2.

This is the answer.