Find V1 and V2 and assume Lambda 002V1 kn 5mAV2 and Vin 0

Find V_1 and V_2, and assume Lambda = 0.02V^-1, k_n = 5mA/V^2 and V_in = 0.5V. V_1 = V_2 =

Solution

From the given figure, we can say that the MOSFET Q1 is ON due to high gate-source voltage of 2.5v and that of Q2 is OFF dut to Vgs is grounded.

As Q1 conducts Vdd =5v appears at V1 terminal hence V1=5 volts

As Q2 doent conduct Vss = -2.5v appears at V2 terminal. So V2= -2.5 volts