Write a method named enough time for lunch that accepts four

Write a method named enough time for lunch that accepts four integers hour 1, minute 2, hour2, and minute2 as parameters. Each pair of parameters represents a time on the 24-hour clock (for example, 1:3 6 PM would be represented as 13 and 36). The method should return true if the gap between the two times is long enough to eat lunch: that is, if the second time is at least 45 minutes after the first time. Otherwise the method should return false. You may assume that all parameter values are valid: the hours are both between 0 and 23, and the minute parameters are between 0 and 59. You may also assume that both times represent times in the same day, e.g. the first time won\'t represent a time today while the second time represents a time tomorrow. Note that the second time might be earlier than the first time; in such a case, your method should return false. Here are some example calls to your method and their expected return results:

Solution

bool enoughTimeForLunch(int h1,int m1,int h2,int m2)

{

int t1 = h1*60 + m1;                                // calculating the first time in terms of minutes

int t2 = h2 * 60 + m2;                              // calculating the second time in terms of minutes

int time = t2 - t1;                                    // Calculating the difference between the 2 time periods in minutes

if ( time >= 45 )                                      // Checking whether the minimum time difference is 45 minutes or more

return(true);                                           // Return true as required by question

else                                                     // If difference between is less than 45 minutes

return(false);                                         // Return false as required by question

}

For Example :

bool enoughTimeForLunch(11,00,11,59)

{

int t1 = h1*60 + m1;                                // t1 = 660

int t2 = h2 * 60 + m2;                              // t2 = 660 + 59

int time = t2 - t1;                                    // time = 660 - (660 + 59) => time = 59

if ( time >= 45 )                                      // if (59 > 45)

return(true);                                           // Return true

else                                                     // Skipped by defaut

return(false);                                         // Skipped by defaut

}