Write a slope intercept equation for a line perpendicular to

Write a slope intercept equation for a line perpendicular to the y =- 3* + 8 and goes through the point (2, -1) Solve for y without a calculator: (5-2y)/3 - (1-y)/2 - y+l/6 A commercial jet airplane climbs at takeoff with slope m = 4/9. Write a linear equation to represent the problem. How far in the horizontal direction will the airplane fly to reach an altitude of 20,000 ft. above the takeoff point? Solve for x by completing the square. Keep Exact. x^2 + 4x - 9 = 2

Solution

10)

2(5 – 2y) – 3(1 - y) = y + 1

10 – 4y – 3 + 3y = y + 1

7 – y = y + 1

2y = 6

y = 3

11)

Slope = m = 4/9

a) Linear equation is

    y = mx = 4/9*x

    4x – 9y = 0

b) y = 20000

then x = 9/4*y = 9/4*20000 = 45000 ft

12) x^2 + 4x – 9 = 2

      x^2 + 4x -11 = 0

      x^2 + 4x + 4 – 15 = 0

     (x + 2)^2 – 15 = 0

    (x + 2)^2 = 15

     x + 2 = +- 3.87

     x = 1.87, -5.87

 Write a slope intercept equation for a line perpendicular to the y =- 3* + 8 and goes through the point (2, -1) Solve for y without a calculator: (5-2y)/3 - (1

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