One side of a rectangular backyard is 2 meters longer than t
One side of a rectangular backyard is 2 meters longer than the other. If the diagonal is 10 meters, then what are the lengths of the sides?
Solution
let width of rectangular backyard = w
therefore, length of teh backyard would be w+2
as, One side of a rectangular backyard is 2 meters longer than the other
diagonal of rectangle = sqrt(w^2+l^2)
here l = (w+2)
diagonal given = 10 m
therefore we can write
10 = sqrt(w^2+l^2)
squareing both sides
100 = w^2 + (w+2)^2
100 = 2w^2 + 4 + 4w
2w^2 + 4w - 96 = 0
on solving the quadratic we get
w = 6
so width of the rectangular backyard = 6 metres
length of the rectangular backyard = (6+2) = 8 metres

