Let A B be 3 Times 3 matrices with detA 3 and detB 2 Find
     Let A, B be 3 Times 3 matrices with det(A) = 3 and det(B) = 2. Find the determinant of A^2 (2B) (3A)^-1.  8/9  16/9  4  8/3  None of the above.   
  
  Solution
det(A2)=(detA)2 =(3)2 = 9
3A means each row of A is multiplied by 3 and this is a 3x3 matrix so determinant will be multiplied by 33
det((3A)-1) = [det(3A)]-1=[33det(A)]-1=1/(27*3)=1/81
det(2B)=23det(B)=16
hence det (A2(2B)(3A)-1)= 9*(1/81)*16=16/9=1.7777

